Looking for: accessing member of a derived class from a pointer to base.
Reductio ad absurdum:
class Base
{
public:
int member_of_base;
};
class Derived : public Base
{
public:
int member_of_derived;
};
I'm currently using templates:
template <class T>
class Client
{
T* data; // T is Base or Derived
};
There are few levels of composition in the class hierarchy, so I have to carry the template type parameter through all of the hierarchy. What is the best approach to overcome this? Obviously I cannot access the member of Derived via a pointer to Base, i.e:
Base* foo = new Derived();
foo->member_of_derived; // no go
Thus, I'm using:
Client<Base>
Client<Derived>
I'm trying to come up with a solution that works without the templates. Options that I know would work:
- void* //plain old C and casting as necessary, they're all pointers (as in memory addresses) in the machine
static_cast<Derived*>(pointer_to_base);
//type safe at compile time.- wrapping the cast in a Client's template method (not to be confused with a design pattern here)
The last option seems to be the most "elegant", i.e:
template <class T>
T* get_data() const { return static_cast<T*>(data); }
However, looking here and there tells me there might exist a way unknown to me. I saw CRTP, but that brings me back to templates, which is the original thing I want to go without. What are the ways, or popular approaches, to achieve such a goal?
The real code uses shared_ptr, weak_ptr and enable_shared_from_this with weak_from_this. I'm looking for a type safe "polymorphic member" access.
EDIT: they're not just "ints". They can be totally different types, as in protobuf in base and Json::Value in derived. And I'm trying to use the pointers to Base/Derived, which in turn would give me access to their respective members.
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