lundi 23 mars 2015

Comparison Operators: Pattern for fewest lines

I've been told that it is possible to write 6 comparison operators ( < , <= , > , >= , == , != ) based on the definition of just one. The pattern supposedly starts with a strict inequality. < for example. By negating <, you can define >=, since they are opposites. I get stuck at this point. Perhaps I am starting from the wrong operator. It's not important of course, but I'm curious. Cheers!


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