Some one posted the questions about this pattern but not having the solution of the question raised in my mind so posting with the queries i have...
In above example if all the instance are initialized by s_prototypes variable, and next time if any object of that will be replaced by new object in clone method then what will happen to existing object?? will it create memory leaks??
As far as I understand from above example two statement are confusing me
class Stooge {
public:
virtual Stooge* clone() = 0;
virtual void slap_stick() = 0;
};
class Factory {
public:
static Stooge* make_stooge( int choice );
private:
static Stooge* s_prototypes[4];
};
int main() {
vector roles;
int choice;
while (true) {
cout << "Larry(1) Moe(2) Curly(3) Go(0): ";
cin >> choice;
if (choice == 0)
break;
roles.push_back(
Factory::make_stooge( choice ) );
}
for (int i=0; i < roles.size(); ++i)
roles[i]->slap_stick();
for (int i=0; i < roles.size(); ++i)
delete roles[i];
}
class Larry : public Stooge {
public:
Stooge* clone() { return new Larry; }
void slap_stick() {
cout << "Larry: poke eyes\n"; }
};
class Moe : public Stooge {
public:
Stooge* clone() { return new Moe; }
void slap_stick() {
cout << "Moe: slap head\n"; }
};
class Curly : public Stooge {
public:
Stooge* clone() { return new Curly; }
void slap_stick() {
cout << "Curly: suffer abuse\n"; }
};
Stooge* Factory::s_prototypes[] = {
0, new Larry, new Moe, new Curly
};
Stooge* Factory::make_stooge( int choice ) {
return s_prototypes[choice]->clone();
}
Output
Larry(1) Moe(2) Curly(3) Go(0): 2
Larry(1) Moe(2) Curly(3) Go(0): 1
Larry(1) Moe(2) Curly(3) Go(0): 3
Larry(1) Moe(2) Curly(3) Go(0): 0
Moe: slap head
Larry: poke eyes
Curly: suffer abuse
But when we call clone method by make_stooge method it will return new object,If that returns new object and replaces it with existing one then the existing object will create memory leak here(because new operator completely creates seperate object and not return existing one here)....
so this thing is confusing me with this example....
Aucun commentaire:
Enregistrer un commentaire