Sed - Print Lines that match two patterns

i have the following problem. My file looks like this :

1082016051300000010005690902BCDEΔ0204366221002201612052016-00001274448A                                                                     
1082016051300000010034397704EDFG10865125102001201626042016-000001028134
1082016051300000010068901401RADJ34835974123112201528042016-000001343290                                                                     
1082016051300000010068901401RADJ34835974103112201528042016-000000910290                                                                     
1082016051300000010095474301RADJ13453401102812201525042016-00000208995K                                                                     
1082016051300000010098429002RADJΤ1052947211312201218042016-000034021290
1032016051300000010095474301RADJ13453401102812201525042016-00000208995K                                                                     
1032016051300000010098429002RADJΤ1052947211312201218042016-000034021290

and i m trying to print only lines that match both patterns, anywhere on the line. I want to print only lines that match two patterns, the first pattern being on columbs 2:1 (08) and the second pattern being the word (RAD). I ve tried to do this with grep :

grep -o '.[0-1][1-8]*RAD' FILEIN

and the only response i get is that FILEIN is a binary file. I ve also tried with sed this :

sed -n '/[0-1][1-8]*RAD/p' FILEIN 

but i have a feelign the * is not expanded. I ve managed to make it work by looking for two patterns in succession, like :

sed -n '/RAD/p' FILEIN | sed '/^108/p' 

and this works, but the file i ll be using as input is potentially huge, and i m not sure that piping a stream into another is time efficient. Could someone help me? Awk or Perl are welcome too. Thank you