Creating an object with the value of a private method

Suppose I have this code:

public Foo {
    public enum Bar {FooBar, BarFoo, FooFoo, BarBar}
    public Foo (Bar bar) {
        //Do something
    }
}

Now, when creating an object, I have several different cases for what migth be created: FooBar, BarFoo, FooFoo, BarBar. Depending on what these cases are, how might I execute a different method for each? I suppose I am looking to do something a bit like this:

public Foo {
    public enum Bar {FooBar, BarFoo, FooFoo, BarBar}
    public Foo (Bar bar) {
        switch (bar) {
            case FooBar: fooBar(bar); break;
            case BarFoo: barFoo(bar); break;
            case FooFoo: fooFoo(bar); break;
            case BarBar: barBar(bar); break;
            default: break;
        }
    }
    void fooBar (Bar bar) {
        //Treat this as the constructor class for case FooBar
    }
    void barFoo (Bar bar) {
        //Treat this as the constructor class for case barFoo
    }
    void fooFoo (Bar bar) {
        //Treat this as the constructor class for case fooFoo
    }
    void barBar (Bar bar) {
        //Treat this as the constructor class for case barBar
    }
}

In addition, is this a bad practice? Would it be better to create a separate class for each case and drop the enum?