C program to match a string against a given pattern without using regex

I have written C code that takes an input str and returns result matching against pattern.

The code does not return the proper result in certain scenarios.

For example, if the input string is "pat.com/xyzabc" and pattern is "pat.*/*abc*", the program does not return a match.

Similarly it does not match pattern "pat.*/*abc" or "pat.com/*abc*".

Please help how can I correct the following code?

int strmatch(const char str[], const char pattern[], 
            int n, int m)  
{
    // empty string 
    if (m == 0)  
        return (n == 0); 

    // initailze lookup table to false 
    int lookup[n + 1][m + 1]; 
    memset(lookup, 0, sizeof(lookup)); 
    // empty pattern can match with empty string 
    lookup[0][0] = 1;  
    // Only '*' can match with empty string 
    for (int j = 1; j <= m; j++) 
        if (pattern[j - 1] == '*') 
            lookup[0][j] = lookup[0][j - 1]; 
    for (int i = 1; i <= n; i++) 
    {   
        for (int j = 1; j <= m; j++) 
        {   
            if (pattern[j - 1] == '*' || pattern[j - 1] == '*') 
                lookup[i][j] = lookup[i][j - 1] ||  
                            lookup[i - 1][j]; 

            else if (str[i - 1] == pattern[j - 1]) 
                lookup[i][j] = lookup[i - 1][j - 1]; 

            // If characters don't match 
            else lookup[i][j] = 0;  
        }   
    }   
    return lookup[n][m]; 
}