How to handle second submission duplicate request If a user was trying to refresh the page because of the first submission is not finished yet.
- client side disabling submit button to avoid multiple submits.
- and handled Post/Redirect/Get pattern after form submit redirect to success view
I believe both are handled well.
class SomeView(View):
def post(self, request, *args, **kwargs):
if form.is_valid()
if request_exists(request):
# here I can raise the exception also
# But How I redirect the customer to sucess page
# If 1st submission got success response.
else:
# here I have called internal api to get/post some data.
# user refreshes before this call has completed.
...
# once getting respose its ALWAYS redirect to new page
return HttpResponseRedirect('/thanks/')
But how to handle the case If delay from getting a response from API call. I need to delay until the first submission finishes. Then I have to send the user to the thanks page.
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