How to deal with exception when building an API wrapper?

I'm trying to build a wrapper for an API. The API can send me all kind of response: 200, 403, 404, 429, 500 now I want my wrapper to be able to handle exceptions, this is my current class:

class API:
    def __init__(self, key):
        self.key = key

    def get_some_object_from_a_endpoint(self):
        call = requests.get("adress_of_a_endpoint&api_key={0}".format(self.key))
        content = call.json()
        my_object = MyClass.build_object_from_api_data(content)
        return my_object

Now I thought about defining a function in my class that will manage all the call and call this function in each of my endpoint, so my class will look like this:

class API:
    def __init__(self, key):
        self.key = key

    @staticmethod
    def check_exception(request):
        if request.status_code == 200:
           return request.json()
        if request.status_code == 404:
            print("Not found")
        ...  # management of other exceptions


    def get_some_object_from_a_endpoint(self):
        call = requests.get("adress_of_a_endpoint&api_key={0}".format(self.key))
        request_result = self.check_exception(call)
        if request_result:
           content = call.json()
           my_object = MyClass.build_object_from_api_data(request_result)
           return my_object
        else:
           return MyClass()

I will use my API wrapper that way:

api = API("my_key")
my_object = api.get_some_object_from_a_endpoint() # Will have the data from the API, the default object or raised some exception depending of the error code

What annoy me with my solution is that for every endpoint I will have the same piece of code:

call = requests.get("adress_of_a_endpoint&api_key={0}".format(self.key))
request_result = self.check_exception(call)
if request_result:
   ...
   return my_object
else:
   return MyClass()

Does my solution respect common design pattern? Is there a better practices for solving this kind of problem?