Pubsub - How to handle connection drop from source?

Below function(BroadcastMessage) broadcast messages to subscribers(PublisherHub.subscribers). BroadcastMessage establishes a connection from source(PCF firehose)

In the below case, BroadcastMessage() establishing a connection from PCF firehose using api consumer.New()(https://github.com/cloudfoundry/noaa/blob/master/consumer/consumer.go#L78):

func BroadcastMessage(publisherHub *publisher.PublisherHub) {
    ....
    cnsmr := consumer.New(dopplerAddress, &tls.Config{InsecureSkipVerify: true}, nil)
    ....
    var (
        msgChan   <-chan *events.Envelope
        errorChan <-chan error
    )

    switch *filterType {
    case "logs":
        msgChan, errorChan = cnsmr.FilteredFirehose(firehoseSubscriptionId, authToken, consumer.LogMessages)
    case "metrics":
        msgChan, errorChan = cnsmr.FilteredFirehose(firehoseSubscriptionId, authToken, consumer.Metrics)
    default:
        msgChan, errorChan = cnsmr.Firehose(firehoseSubscriptionId, authToken)
    }

    go func() {
        for err := range errorChan {
            fmt.Fprintf(os.Stderr, "%v\n", err.Error())
        }
    }()

    for msg := range msgChan {
        publisherHub.Broadcast <- msg
    }
}

---

publisherHub broadcast msg to all subscribers where type PublisherHub maintains the hub of subscribers:

type PublisherHub struct {
    subscribers map[*subscriptionmediator.HandlerSubscription]struct{}
    Register    chan *subscriptionmediator.HandlerSubscription
    Unregister  chan *subscriptionmediator.HandlerSubscription
    Broadcast   chan *events.Envelope
}

---

main() blocks in BroadcastMessage() until explicit shutdown through SIGTERM

func main() {

    ....
    publisherHub := publisher.NewHub()
    go publisherHub.Run()
    ....
    go loadbroadcast.BroadcastMessage(publisherHub)
    ....   
}

---

But in production this connection(consumer.New()) is being lost due to loss of network connectivity and all the subscribers are getting affected.

---

How to handle loss of connection in BroadcastMessage, so that subscribers can receive messages seamlessly? Because Broadcastmessage() is already in an infinite loop(for msg := range msgChan)