regular expression on method Pattern.compile()

i have to create a regular expression to put into the method Pattern.compile(regex); My regex has to allow integer (without 0 at the beginning of the number),a sequence of numbers and char (A-Za-z),but the problem is the third point: a string that must begin and end with the char ' " ', must avoid the chars backslash (unless there isn't one other backslash) and the char '"' (unless there is before a backslash)

but i don't understand how to do the second point ( i have met a lot of errors), this is my java code:

public static void main(String[] args) {
    if (args.length == 0)
        throw new IllegalArgumentException();
    Matcher matcher = Pattern.compile("([a-zA-Z]+[0-9a-zA-Z_]*)|"
            + "(0(?![0-9])|([1-9]+)([0-9]*))|" //"?!" è una asserzione : " se la condizione tra parentesi è vera non considerare lo zero
            + "([\"]{1}(([\\\\][^\"\\][\\\"])*)[\"]{1})" 
            + "|(\\s+)").matcher(args[0]);// \s = [ \t\n\x0B\f\r]
    System.out.println("Input: " + args[0]); //println va a capo dopo la stampa
    while (matcher.lookingAt()) {
        System.out.print("Lexeme '" + matcher.group() + "'"); //non va a capo dopo la stampa
        System.out.println(" group " + ExampleLexer.getGroup(matcher));
        matcher.region(matcher.end(), matcher.regionEnd());
    }

     //attenzione: matcher.hitEnd() restituisce true se il matcher arriva in fondo
     //all'input anche se l'ultimo match non ha avuto successo, quindi funziona solo
     //per espressioni regolari "semplici"
    if (matcher.regionStart() == matcher.regionEnd())
        System.out.println("All lexems succesfully matched");
    else {
        System.err.print("Unmatched lexem ");
        matcher.usePattern(Pattern.compile(".*"));
        matcher.lookingAt();
        System.err.println(matcher.group());
    }
}